解:y/3+(x+1)/6=3,方程两边同乘以6,整理得2y+x=5;------(1)
2(x+y/2)=3(x+y/18),去括号并整理得:6x+7y=0.-------------(2)
(1)×6-(2),得:12y+6x-(6x+7y)=30-0, 即5y=30,y=6.
把y=6代入2y+x=5,得:x= -7.
所以方程组的解为:x= -7, y=6.
y/3 - x/6 + 1 = 3
2(x-y/2) = 3(x+y/18)
化简分别得到:
2y - x = 12
-y = x + y/6
上式两边一减,消去了x,得到 3y = 12- y/6,所以 y= 72/19 , 所以 x = 2y - 12 = 144/19 - 12
= -84/19
y/3 - (x + 1)/6 = 3
2(x-y/2) = 3(x+y/18)
化简分别得到:
2y-x = 19
x=-7/6y
两式相加
2y=19-7/6y
移项 19/6y=19 得y=6
由x=-7/6y 得到x=-7
x=-84/19
y=72/19
x=-7,y=6?你确定没搞错?