e^y = xyy= lnx + lnyy' = 1/x + (1/y) y'y' [(y-1)/y] = 1/xy' = [y/(y-1)](1/x) y'' =[y/(y-1)](-1/x^2) + (1/x)( -1/(y-1)^2 )y'=-y/[x^2(y-1)] + (1/x)( -1/(y-1)^2 ) .[y/(y-1)](1/x) =-y/[x^2(y-1)] - y/[x^2(...
