lim(x->-8) [√(1-x) -3 ]/ (2+√x)=lim(x->-8) [√(1-x) -3 ] (2-√x)/ (4-x)=5 lim(x->-8) [√(1-x) -3 ] / (4-x)=5 lim(x->-8) [(1-x) -9 ] / { (4-x) . [√(1-x) +3 ] }=5 lim(x->-8) (-8-x) / { (4-x) . [√(1-x) +3 ] }=0
