若x方加y方加四x减六y加十三等于零求xy方的值

2025-05-21 12:49:33
推荐回答(1个)
回答1:

x^2+y^2+4x-6y+13=0
(x+2)^2+(y-3)^2=0

x=-2, y=3

xy^2=-2*(3)^2=-18
xy=-6.
(xy)^2=36