组成为CH4O和C3H8O的混合醇,在一定条件下进行脱水反应,最多能生成的有机物的种数为(  )

2025-05-19 14:34:35
推荐回答(1个)
回答1:

CH4O只有CH3OH一种结构
C3H8O有
CH3CH2CH2OH CH3CH(OH)CH3
CH3OCH2CH3

脱水时可能发生的反应有
CH3OH+CH3CH2CH2OH=CH3OCH2CH2CH3+H2O
CH3OH+CH3CH(OH)CH3=CH3CH(CH3)OCH3+H2O
CH3CH(OH)CH3= CH2=CHCH3+H2O
2CH3OH = CH3OCH3 +H2O
2CH3CH2CH2OH = CH3CH2CH2OCH2CH2CH3 +H2O
2CH3CH(OH)CH3 = CH3CH(CH3)OCH(CH3)CH3 +H2O
CH3CH2CH2OH+CH3CH(OH)CH3 = CH3CH(CH3)OCH2CH2CH3 +H2O
上面7个反应,一共7种产物

1.C3H8O可以代表2种醇,再加上CH3OH,共3种醇。
2.三种醇组合起来生成6种醚
3.但C3H8O还能脱水生成1种烯

我只写碳架 你自己加上氢原子
C-O-C

C-C-C-O-C

C-C-O-C
....|
....C

C-C-C-O-C-C-C

C-C-O-C-C
.....|.......|
....C.....C

C-C-O-C-C-C
.....|
....C

C=C-C

满意请好评