Blog2 (1+s/(n0B))=log2 (1+s/(n0B))^B利用重要极限lim(n->∞)(1+1/n)^n=e原式=log2 lim(B->∞)(1+s/(n0B))^B=log2 lim[(1+1/(n0B/s))^(n0B/s)]^(s/n0)=log2 e^(s/n0)=s/n0log2 e解答完毕。
log2换个底,再套一下等价无穷小 ln(1+x)~x。