数学高手进!!在线等,急急急!!!!(导数)

求下列函数的导数y = xcos(2x + π/2)sin(2x + π/2)
2025-05-11 16:05:06
推荐回答(2个)
回答1:

y = xcos(2x + π/2)sin(2x + π/2)
y=1/2 Xsin(4x+π)
=-1/2Xsin(4x)
y'=-1/2(sin(4x)+4xcos(4x))

回答2:

y'=cos(2x + π/2)sin(2x + π/2)-2x[sin(2x + π/2)^2+2x[cos(2x + π/2)]^2
=sin(4x + π)/2+2xcos(4x +π)
=-(sin4x )/2-2xcos4x