如图所示,用长L的绝缘细线拴住一个质量为m,带电荷量为q的小球,线的

2025-05-13 06:45:49
推荐回答(1个)
回答1:

h = Lsin60° = √3×L/2

(1)
qUBA = - mgh
UBA = - mgh/q
= - √3mgL/(2q)
(2)
E = UAB / (Lcos60°)
= √3mgL/(2q) / (L/2)
= √3mg / q