已知△ABC:(1)如图1,BO、CO分别为∠ABC,∠ACB的平分线,相交于O.①如果∠ABC=50°,则∠OBC=______

2025-05-22 19:44:58
推荐回答(1个)
回答1:

(1)①∵BO平分∠ABC,
∴∠OBC=

1
2
∠ABC=25°;
②∵OB、OC分别为∠ABC,∠ACB的平分线,
∴∠ABC=2∠OBC,∠ACB=2∠OCB.
∵∠A=180°-(∠ABC+∠ACB),
∴∠A=180°-2(∠OBC+∠OCB),
∴∠A=180°-2(180°-∠BOC),
∴∠A=-180°+2∠BOC,
∴2∠BOC=180°+∠A,
∴∠BOC=90°+
1
2
∠A.

(2)∵BP、CP分别是∠ABC与∠ACB的外角平分线,
∴∠CBP=
1
2
∠CBM,∠BCP=
1
2
∠BCN,
∴∠CBP+∠BCP
=
1
2
∠CBM+
1
2
∠BCN
=
1
2
(∠CBM+∠BCN)
=
1
2
(∠A+∠ACB+∠A+∠ABC)
=
1
2
(180°+∠A),
∴∠BPC=180°-(∠CBP+∠BCP)
=180°-
1
2
(180°+∠A)
=90°-
1
2
∠A
=90°-
1
2
x°.