设桃树有x棵,则梨树有(550-x)棵。根据题意有
4x/5=2(550-x)/3
4x/5+2x/3=1100/3
22x/15=1100/3
x=1100*15/(3*22)
x=250 棵
即桃树有250棵
梨树有550-250=300 棵
请参考
解:设梨树有X棵,则桃树有(550-X)棵
2/3X=(550-X)×4/5
2/3X=440-4/5X
2/3X+4/5X=440
22/15X=440
X=440÷22/15
X=300
则桃树有:550-300=250(棵)
答:梨树有300棵,桃树有250棵。
设桃树为X棵,梨树为Y棵
X+Y=550
4X/5-2Y/3=0
Y=300棵
550-300=250棵