如图,已知△ABC, BD DC = 2 3 , AE EC = 3 4 ,AD、BE交于F

2025-06-23 00:10:41
推荐回答(1个)
回答1:

作EG BC交AD于G,
BD
DC
=
2
3
AE
EC
=
3
4

AE
AC
=
3
7

GE
CD
=
3
7

GE
BD
=
9
14

BF
FE
=
14
9

作DH AC交BE于H,则DH=
2
5
CE=
8
15
AE,
AF
FD
=
AE
DH
=
15
8

AF
FD
?
BF
FE
=
14
9
×
15
8
=
35
12

故选C.