解:∵∠ADC=∠B+∠BAD,∠ADC=∠ADE+∠EDC∴∠B+∠BAD=∠ADE+∠EDC∵AD=AE∴∠ADE=∠AED∵∠AED=∠EDC+∠C∴∠B+∠BAD=2∠EDC+∠C∵AB=AC∴∠B=∠C∴∠BAD=2∠EDC∴∠EDC=∠BAD/2=30/2=15°如果我的答案对您有帮助,请点击右面的“采纳答案”按钮!祝您生活愉快,学习进步!谢谢!