(1)已知x+y=3,x的二次方+y二次方=7,求xy的值 (2)已知a+2b=5,ab=2,求(a-2b)的为次方的值

2025-05-18 22:17:10
推荐回答(1个)
回答1:

解1由x²+y²=7
得x²+y²+2xy-2xy=7
即(x+y)²-2xy=7
即(3)²-2xy=7
即2xy=2
即xy=1
2(a-2b)的2次方
=(a-2b)²
=a²-4ab+4b²+8ab-8ab
=a²+4ab+4b²-8ab
=(a+2b)²-8ab
=5²-8*2
=25-16
=9