用秦九诏算法求多项式f(x)=2x五次方+3x四次方+2x三次方-4x+5,当x=2时的值

2025-05-18 22:09:21
推荐回答(1个)
回答1:

f(x)=2x^5+3x^4+2x^3-4x+5
=>f(x)=(2x^4+3x^3+2x^2-4 )*x+5
=>f(x)=((2x^3+3x^2+2x )*x-4 )*x+5
=>f(x)=(((2x^2+3x+2) *x )*x-4 )*x+5
=>f(x)=(((( 2x+3 ) *x+2)* x )* x-4 )*x+5
=>f(2) = (((( 2*2+ 3) *2+ 2) *2)*2 - 4)*2 +5
=125