解：3(x+1)(x-1)-3(x-1)^2+2=8 3(x-1)[(x+1)-(x-1)]=66(x-1)=6x=2
3(x+1)(x-1)-3(x-1)^2+2=8 (x +1)(x-1)-(x-1)^2=2x²-1-x²-1+2X=22x=4x=2
3(x+1)(x-1)-3(x-1)^2+2=83(x²-1)-3(x²-2x+1)-6=03x²-3-3x²+6x-3-6=06x=12x=2
