求lim(N→∞)[1+ (2nx +x^2)⼀2n^2]^(-n)

2025-05-21 01:56:23
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回答1:

lim(n→∞) [1+(2nx+x²)/2n²]^(-n)
=lim(n→∞) [1+(2nx+x²)/2n²]^{[2n²/(2nx+x²]*[2nx+x²)/2n²]*(-n)}
=e^lim(n→∞) [2nx+x²)/2n²]*(-n)
=e^(-x)