(2x^2y-4xy^2)-(-1⼀2xy^2+x^2y)其中x=-1,y=2,先化简再求值,好的追加100分

2025-05-19 03:51:26
推荐回答(3个)
回答1:

首先展开括号, 得 2x^2y-4xy^2+1/2xy^2-x^2y
移项得 2x^2y-x^2y-4xy^2+1/2xy^2
合并得 x^2y-7/2xy^2
提取xy 得 xy(x-7/2y)

带入值 -2(-1-7)=16

回答2:

(2x^2y-4xy^2)-(-1/2xy^2+x^2y)
=2x²y-4xy²+1/2xy²-x²y
=x²y-7/2xy²
当x=-1,y=2时
原式=x²y-7/2xy²
=(-1)²×2-7/2×(-1)×2²
=2+14
=16

回答3:

原式=2x^2y-4xy^2+1/2xy^2-x^2y
=x^2y-7/2xy^2
=1×2+7/2×4
=2+14
=16