X+1/Y=4Y+1/Z=1Z+1/X=7/3消元后得到二元二次方程组，解得：X=3/2，Y=2/5，Z=5/3所以XYZ=1方程解起来挺烦得，我解了好一会而，要有耐心哦解法二(X+1/Y)(Z+1/X)(Y+1/Z)=XYZ+1/(XYZ)+X+Y+Z+1/X+1/Y+1/Z=XYZ+1/(XYZ)+4+1+7/3=4*1*7/3得到：XYZ+1/(XYZ)=2,解得XYZ=1
