an=2Sn^2/(2Sn-1)
2an*Sn-an=2Sn^2,因为an=Sn-S(n-1)
so,2[Sn-S(n-1)]*Sn-Sn+S(n-1)=2Sn^2
so,S(n-1)-Sn=2S(n-1)*Sn
so,[1/Sn]-[1/S(n-1)]=2
so,[1/S(n-1)]-[1/S(n-2)]=2
.
.
.
.
so,[1/S2]-[1/S1]=2
全部相加,得到:[1/Sn]-[1/S1]=2(n-1)
S1=a1=1
so,1/Sn=2n-1
Sn=1/(2n-1),带入an=2Sn^2/(2Sn-1) ,得到:an=(-2)/[(2n-3)*(2n-1)]