说话算话??
f(x)=ax^5-bx^3+cx-6=17
f(-3)=ax^5-bx^3+cx-6=17
令g(x)=ax^5-bx^3+cx
f(-3)=g(-3)-6=17
g(-3)=23,g(x)是奇函数! g(3)= -g(-3)= -23
所以f(3)=g(3)-6=-23-6= -29
望采纳,谢谢!!!!!!!!!!!!!
x=-3;a*(-3)^5-b*(-3)^3+c*(-3)-6=17;
a*(-3)^5-b*(-3)^3+c*(-3)=23;
a*(3^5)+b*3^3+3c=-23;
x=3;原式=a*(3)^5+b*(3)^3+c*(3)-6=-23-6=-29;