已知xy为实数且y=√(x-1⼀2)+√(1⼀2-x+1⼀2),求xy的值

2025-05-18 05:52:02
推荐回答(1个)
回答1:

因为Y=根号下X-1/2+根号下1/2-X+1/2
所以要想使根号下X-1/2+根号下1/2-X有意义,则有x-1/2=0
x=1/2
y=1/2
带入5X+(2Y-1)-根号下Y*2-2Y+1
=5x+2y-1-(y-1)
=5x+y
=3