1)如图1,△ABC中,AB>AC,AD平分∠BAC交BC于点D,在AB上截取AE=AC,过点E作EF‖BC交AD于点F.求助啊!!!!

2025-05-21 17:51:10
推荐回答(1个)
回答1:

(3)如图2
AB=AC
∠B=∠BAC=∠FEB
ADE≌△ADC ∠ACD=∠AED ∠FCA=90-∠ACD ∠FEB=90-∠AED
∠FCA=∠FEB=∠B=∠BAC
∠ACD=∠B+∠BAC=2∠FCA=90-∠FCA
∠FCA=30=∠FEB
FG==1÷√3