解：原式=[(m²-2m+1)/(m²-1)]÷[m-1-(m-1)/(m+1)]={(m-1)²/[(m+1)(m-1)]}÷{[(m-1)(m+1)-(m-1)]/(m+1)}=[(m-1)/(m+1)]÷[m(m-1)/(m+1)]=[(m-1)/(m+1)]×{(m+1)/[m(m-1)]}=1/m
