已知数列{an}的通项公式为an=2^(n-1)+1,则a1×Cn0+a2×Cn1……+a(n+1)×Cnn=?

2025-05-14 11:56:47
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回答1:

a1×Cn0+a2×Cn1……+a(n+1)×Cnn
=(2^0+1)*C(n,0)+(2^1+1)C(n,1)+(2^2+1)C(n,2)+.......+(2^n +1)*C(n,n)
=[2^0*C(n,0)+2^1*C(n,1)+2^2*C(n,2)+.......+2^n *C(n,n)]+[C(n,0)+C(n,1)+C(n,2)+.......+C(n,n)]
=(1+2)^n+2^n
=3^n+2^n