用隐函数求导法则:2y-ty^2+e^t=52y'-y^2-2ty*y'+e^t=0(2-2ty)y'=y^2-e^ty'=(y^2-e^t)/(2-2ty)
2y'-2tyy'=02y'(1-2ty)=0y'=0或者y=1/2t