求数列1,-3,5,-7,9,-11,...前n项的和

2025-06-23 05:29:42
推荐回答(1个)
回答1:

Sn=(1-3)+(5-7)+..................+(2n-1)*(-1)n次放
=-2+(-2)+...........+(2n-1 )的n次方
当n为偶数时
Sn=-2 x n/2=-n
当n为奇数时
Sn=-2x (n-1)/2+2n-1=-(n-1)+2n-1=n
不懂继续问哦^_^