我确定楼上算错了。不要听他的。令2x+π/3=kπ求得x=[（3k-1）π]/6
T = (2π)/2 = π一个对称轴为2x + π/3 = 0 => x = -π/6每半个周期一个对称轴所以对称轴方程为x = kT/2 - π/6 = k/2 * π - π/6
2x+π/3=2kπ2x=2kπ-π/3x=kπ-π/6 (k=Z)
