先能明白(1)小题的解答过程,再解答第(2)小题,(1)已知a2-3a+1=0,求a2+1a2的值.解:由a2-3a+1=0

2025-05-20 04:11:00
推荐回答(1个)
回答1:

由y2+3y-1=0,知y≠0,∴y+3-

1
y
=0,即
1
y
-y=3,
(
1
y
?y)2
=
1
y2
+y2-2=9,即
1
y2
+y2=11,
(
1
y2
+y2)2
=121,
1
y4
+y4=119,
y8?3y4+1
y4
=y4-3+
1
y4
=116,
y4
y8?3y4+1
=
1
116