如果m、n是两个不相等的实数,且满足m 2 -2m=1,n 2 -2n=1,那么代数式2m 2 +4n 2 -4n+1994=______

2025-06-22 02:36:10
推荐回答(1个)
回答1:

根据题意可知m,n是x 2 -2x-1=0两个不相等的实数根.
则m+n=2,
又m 2 -2m=1,n 2 -2n=1
2m 2 +4n 2 -4n+1994
=2(2m+1)+4(2n+1)-4n+1994
=4m+2+8n+4-4n+1994
=4(m+n)+2000
=4×2+2000
=2008.