求函数的最小正周期:y= tanx+1/tanx

2025-06-22 14:19:11
推荐回答(1个)
回答1:

y=tanx+cotx >> y=sinx/cosx+cosx/sinx >> y=(sinx^2+cosx^2)/cosxsinx
=1/sinxcosx
=2/2sinxcosx
=2/sin2x
>>T=2π/2=π