(1)已知x=1,y=-1,求代数式2x 2 y-3xy 2 +4x 2 y-5xy 2 的值.(2)已知a=-2,b=-1,c=3,求代数式5ab

2025-05-19 22:57:02
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回答1:

(1)2x 2 y-3xy 2 +4x 2 y-5xy 2 =(2x 2 y+4x 2 y)-(3xy 2 +5xy 2 )=6x 2 y-8xy 2
当x=1,y=-1时,原式=6×1 2 ×(-1)-8×1×(-1) 2 =-14;

(2)5abc-2a 2 b+[3abc-(4ab 2 -a 2 b)]=5abc-2a 2 b+(3abc-4ab 2 +a 2 b)=5abc-2a 2 b+3abc-4ab 2 +a 2 b=8abc-a 2 b-4ab 2
当a=-2,b=-1,c=3时,原式=8×(-2)×(-1)×3-(-2) 2 ×(-1)-4×(-2)×(-1) 2 =60.