已知A(3,-4),B(-9,2),在直线AB上有一点P,满足AP=12PB,则点P的坐标为(  )A.(3,-4)B.(

2025-05-23 02:32:16
推荐回答(1个)
回答1:

设P(x,y),∵满足

AP
=
1
2
PB
,∴(x-3,y+4)=
1
2
(-9-x,2-y).
x?3=
1
2
(?9?x)
y+4=
1
2
(2?y)
,解得
x=?1
y=?2

∴P(-1,-2).
故选D.