原式= (x+y)2?(x?y)2 x2?y2 ? y2?x2 x2y2 = x2+2xy+y2?x2+2xy+y2 (x+y)(x?y) ?(- (x+y)(x?y) x2y2 )=4xy? ?1 x2y2 =? 4 xy ,则当x=2+ 3 ,y=2- 3 时,原式=? 4 (2+ 3 )(2? 3 ) =- 4 22?(