先化简,再求值:(x+yx?y?x?yx+y)?(1x2?1y2),其中x=2+3,y=2-3

先化简,再求值:(x+yx?y?x?yx+y)?(1x2?1y2),其中x=2+3,y=2-3.
2025-05-22 16:17:03
推荐回答(1个)
回答1:

原式=

(x+y)2?(x?y)2
x2?y2
?
y2?x2
x2y2

=
x2+2xy+y2?x2+2xy+y2
(x+y)(x?y)
?(-
(x+y)(x?y)
x2y2

=4xy?
?1
x2y2

=?
4
xy

则当x=2+
3
,y=2-
3
时,原式=?
4
(2+
3
)(2?
3
)
=-
4
22?(