若数列{a n }满足a 1 =2,a n+1 =3a n +2(n∈N * ),则通项公式a n =________.

2025-06-23 08:10:23
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回答1:

3 n -1
由题意a n+1 =3a n +2,可得a n+1 +1=3(a n +1)
∴{a n +1}是以a 1 +1=3为首项,q=3为公比的等比数列
a n +1=3•3 n-1 =3 n 故a n =3 n -1
故答案为 3 n -1