已知两点A(-1,0),B(1,0),且点C(x,y)满足(x?1)2+y2|x?4|=12,则|AC|+|BC|=(  )A.6B.2C

2025-05-22 20:47:33
推荐回答(1个)
回答1:

(x?1)2+y2
|x?4|
1
2

(x?1)2+y2
x 2?8x+16
=
1
4
,整理求得
x2
4
+
y2
3
=1,点C的轨迹为椭圆
∴根据椭圆的定义可知|AC|+|BC|=2a=4
故选C