求学霸解下图高二数学题,谢谢

2025-05-15 20:33:19
推荐回答(1个)
回答1:

|1-(x-1)/3)|<=2
-2=<1-(x-1)/3<=2
-3=<-(x-1)/3<=1
-3=p={x|-2=┐p={x|x<-2或者x>10}
x^2-2x+1-m^2<=0 (m>0)
(x-1)^2<=m^2
-m=q={x|1-m=┐q={x|x<1-m或者x>m+1}
┐p是┐q的必要而非充分条件
1-m<=-2
m>=3
m+1<=10
m<=9
实数m的取值范围:3=