(x+y)^2+4(x十y一1)因式分解

2025-05-23 10:45:37
推荐回答(3个)
回答1:

(x+y)²+4(x+y-1)
=x²+2xy+y²+4x+4y-4
=x²+4x+4+y²+4y+4+2xy-12
=(x+2)²+(y+2)²+2xy-12

回答2:

回答3:

(x+y+2)平方-6