设中点为M(x,y),A(x1,y1),则B(2x-x1,2y-y1),AP垂直于PB,(x1-4)*(2x-x1-4)+(y1-0)*(2y-y1-0)=0AP^2+BP^2=AB^2A在圆上,x1^2+y1^2=36B在圆上,(2x-x1)^2+(2y-y1)^2=36由以上四式化简得x^2+y^2-32x-40=0