y=cos(2x-π/3)令2x-π/3=kπ+π/2,k∈z得x=kπ/2+5π/12,k∈z所以函数y=cos(2x-π/3)的对称中心是(kπ/2+5π/12,0),k∈z令2x-π/3=kπ,k∈z得x=kπ/2+π/6,k∈z所以函数y=cos(2x-π/3)的对称轴是x=kπ/2+π/6,k∈z
