已知等差数列{an}中,a1>0 3a8=5a13 则Sn中最大时n的值

2025-05-24 06:15:20
推荐回答(2个)
回答1:

解:根据题意:首项为a1,公差为d
3a8=5a13
因为:a8=a1+7d
a13=a1+12d
所以:
3(a1+7d)=5(a1+12d)
3a1+21d=5a1+60d
a1=-19.5d
即:a20=a1+19d>0
a21=a1+20d<0
所以m=20

回答2:

3A8=3A1+21D.......1
5A13=5A1+60D.......2
联立12得3A1+21D=5A1+60D===>2A1=-39D ===>A1=-19.5D
则A1+19D>0 A1+20D<0 所以M=20