已知x=√3+1,y=√3-1,求下列各式的值

(1)x²+2xy+y²(2)x²-y²
2025-05-19 06:33:45
推荐回答(4个)
回答1:

1:x²+2xy+y²=(x+y)²=(2√3)²=12

2:x²-y² =(x+y)(x-y)=2√3*2=4√3

回答2:

1=>(X+Y)2=12
2=>(X+Y)(X-Y)=4根号3

回答3:

(1)x²+2xy+y²=(x+y)²=12
(2)x²-y² =(x+y)*(x-y)=4√3

回答4:

(1) (x+y)*(x+y)=12
(2)(x-y)*(x+y)=4√3