有条件一，x-z+m=1,由条件二，y-z-2=0, m-2=0(改题了),解得m=2,x=z-1,y=z+2,∴(1/2)[(x-y)^(m-1)+(y-z)^m+(z-x)^2]=(1/2)[-3+4+1]=1.
