(1)∵
=P甲 P乙
=
ρ1gh
ρ2gh
=ρ1 ρ2
,5 6
∴
=ρ1 ρ2
.5 6
(2)根据压强公式得:
=F1 F2
=
P甲S甲
P乙S乙
×5 6
=2 1
.5 3
(3)根据阿基米德原理得:
=FA FB
=
ρ1gVA
ρ2gVB
×5 9
=3 2
.5 6
(4)当A、B浸没在液体中,容器底受到的压强之比,
=
P
P
=
F
S甲
F
S乙
×
F
F
=S乙 S甲
×3 2
=1 2
,3 4
∵
=
P
P
=
ρ1gh1
ρ2gh2
×5 6
=h1 h2
,3 4
∴
=h1 h2
.9 10
故选D.