A(n) = a2^(n-1), n = 1,2,...S(n) = a[2^n - 1], n = 1,2,...48 = a2^(n-1),93 = a[2^n-1]=a2^n - a = 2[a2^(n-1)] - a = 2*48 - a = 96 - a, a = 3.48 = a2^(n-1)=3*2^(n-1),16 = 2^(n-1),n = 5.
