请问不定积分怎么求

2025-05-16 16:35:39
推荐回答(1个)
回答1:

∫[(3x⁴-3x²+5x²)/(1+x)]dx
=∫[(3x⁴-3x²+5x²)/(1+x)]dx
=∫[3x²(x-1)+(5x²-5+5)/(1+x)]dx
=∫[3x³-3x²+5x-5+5/(1+x)]dx
=¾x⁴-x³+2.5x²-5x+5ln|x+1|+C