解下列方程组:(1),x+y⼀3+x-y/2=6,3(x+y)-2(x-y)=28; (2

2025-05-16 05:35:30
推荐回答(2个)
回答1:

①x+y/3+x-y/2=6
3(x+y)-2(x-y)=28

2x+2y+3x-3y=36
3x+3y-2x+2y=28

5x-y=36
x+5y=28

5x-y=36
5x+25y=140

26y=104
y=4
x=8
②1式+2式×2得出:8x+13z=31(式4);
2式×3-3式 得出:x+2z=5(式5);
上面两式可得: 3z = 9;
所以:z = 3;
带入(式4),则,x=-1;
将x=-1,z=3带入第一式 则:y=0.5

回答2:

①+②×2,得8x+13z=31 ④ ②×3-③,得4x+8z=20 ⑤ ④-⑤×2,得-3z=-9,解得 z=3 代入⑤,解得x=-1 代入①,解得y=0.5