当x=2-1时,代数式x2?2x+1x+1÷x?1x2+x+x的值是______

当x=2-1时,代数式x2?2x+1x+1÷x?1x2+x+x的值是______.
2025-05-14 15:00:08
推荐回答(1个)
回答1:

原式=

(x?1)2
x+1
?
x(x+1)
x?1
+x
=x(x-1)+x
=x2-x+x
=x2
当x=
2
-1时,原式=(
2
-1)2=2+1-2
2
=3-2
2

故答案为:3-2
2