(2x-a)(3x+b)=6x²+11x-10
∴2b-3a=11 (1)
(2x+a)(x+b)=2x²-9x+10
∴a+2b=-9 (2)
由(1),(2)解得
a=-5, b=-2
(2x-a)(3x+b)=6x^2+(2b-3a)x-ab=6x^2+11x-10
2b-3a=11 ......(1)
ab=10
(2x+a)(x+b)=2x^2+(a+2b)x+ab=2x^2-9x+ab
a+2b=-9 ....(2)
ab=10
(2)-(1): 4a=-20, a=-5
2b=-9-a=-9-(-5)=-4, b=-2
所以 a=-5, b=-2
但 ab=(-5)(-2)=10
正确
(2x-a)*(3x+b)
=6x²+(2b-3a)-ab
=6x²+11x-10
∴2b-3a=11
(2x-a)*(x+b)
=2x²+(2b+a)x+ab
=2x²-9x-10
∴2b+a=-9 ①
∵2b-3a=11 ②
②-①得出,a=-5,b=-2