数学问题！！！急！！！！

解：
∵2x²+4xy+5y²-4x+2y+5=0
(x²+4xy+4y²)+(x²-4x+4)+(y²+2y+1)=0
(x+2y)²+(x-2)²+(y+1)²=0
∴x+2y=0 且 x-2=0, y+1=0
∴x=2, y=-1

(3x²y)²×(-8/3)xy³÷(-4x^4y²)
=3²×(x²)²×y²×(-8/3)×x×y³÷(-4x^4y²)
=9×(-8/3)÷(-4)×(x^4×x÷x^4)×(y²×y³÷y²)
=6×x^(4+1-4)×y^(2+3-2)
=6xy³
=6×2×(-1)³
=6×2×(-1)
=-12

解：
∵2x²+4xy+5y²-4x+2y+5=0
(x²+4xy+4y²)+(x²-4x+4)+(y²+2y+1)=0
(x+2y)²+(x-2)²+(y+1)²=0
∴x+2y=0 且 x-2=0, y+1=0
∴x=2, y=-1

(3x²y)²×(-8/3)xy³÷(-4x^4y²)
=3²×(x²)²×y²×(-8/3)×x×y³÷(-4x^4y²)
=9×(-8/3)÷(-4)×(x^4×x÷x^4)×(y²×y³÷y²)
=6×x^(4+1-4)×y^(2+3-2)
=6xy³
=6×2×(-1)³
=6×2×(-1)
=-12
、采纳一下哦

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