已知sin(a-π⼀4)=3⼀5 ,π⼀4<a<3⼀4π 求(1)cos(a-π⼀4)(2)求sina的值

2025-05-22 17:49:54
推荐回答(1个)
回答1:

π/40
sin(a-π/4)=3/5 cos(a-π/4)=4/5【根据公式】
sina=sin(a-π/4+π/4)=sin(a-π/4)*sinπ/4+cos(a-π/4)*cosπ/4=10分之7倍的根2
y=cos(x-π/4)=sin[π/2-(x-π/4)]=sin(3/4π-x)=-sin(x-3/4π),s所有将sinx先向右移3/4π个单位,然后为x轴对称翻转